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Acrorip V812 Crack [Updated-2022]



 


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Download "MaxMoney" steam key generator for all game.Q: Python print return value I have the following code: import datetime import sys import os import psycopg2 now = datetime.datetime.now() CONNECTION_STRING = "dbname = user = " connection = psycopg2.connect(CONNECTION_STRING) cur = connection.cursor() cur.execute("SELECT * FROM one_table") for row in cur.fetchall(): print(row) I'm wondering how this program returns a tuple instead of a single record. If you are unfamiliar with SQL please refer to my previous question: Return multiple rows in a single column in SQL Also, if it matters, here is the schema for one_table: table one_table ( id_column number(11), date_column date, message_column text, ... ); A: In the first iteration, cur.fetchall() returns a list of tuples. In the next iteration, each tuple becomes a single row, so you get a single row of tuples: >>> cur.fetchall() [('row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1')] >>> [t for t in cur.fetchall()] ['row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1'] To get a single row from a list of rows, you need to do something like the following. cur.execute("SELECT * FROM one_table") for row in cur.fetchall(): print(row) The result is a single row, a list of tuples: [('row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1', 'row 1',

 

 

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Acrorip V812 Crack [Updated-2022]
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